50=4x^2+24x

Solution for 50=4x^2+24x equation:

50=4x^2+24x

We move all terms to the left:

50-(4x^2+24x)=0

We get rid of parentheses

-4x^2-24x+50=0

a = -4; b = -24; c = +50;
Δ = b2-4ac
Δ = -242-4·(-4)·50
Δ = 1376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1376}=\sqrt{16*86}=\sqrt{16}*\sqrt{86}=4\sqrt{86}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{86}}{2*-4}=\frac{24-4\sqrt{86}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{86}}{2*-4}=\frac{24+4\sqrt{86}}{-8}
$